6. How much kinetic energy does a 160 gm cricket ball have when it is thrown with velocity of \( 22 \mathrm{n} / \mathrm{sec} \) ? (a) 176 J (b) 1.76 J (c) 3872 J (d) 38.72 J 7. Which of the following is a wrong example of friction? (a) washing machine pushed along a floor, (b) Sled sliding across snow, (c ) A person sliding down a slide (d) A person lifting a heavy object. 8. The moment of Inertia of a body is \( 100 \mathrm{Kg}-\mathrm{m}^{2} \). If Torque of \( 50 \mathrm{~N}=\mathrm{m} \). is applied on this body, the tangular acceleration produced in the is given by (a) \( 2 \mathrm{rad} / \mathrm{s}^{2} \) (b) \( 1.5 \mathrm{rad} / \mathrm{s}^{2} \) (c) 1 \( \mathrm{rad} / \mathrm{s}^{2} \) (d) \( 0.5 \mathrm{rad} / \mathrm{s}^{2} \) 9. Find the capillary rise of water in a glass tube is 29.4 cm . When the tube radius is doubled, the capillary rise will be equal to (a) 14.7 cm (b) 29.4 cm . (c) 43.1 (d) 7.35 cm 10 The difference of temperature between two bodies is \( 15^{\circ} \mathrm{C} \). The difference in temperature in Kutvin scale is (a) \( 27^{\circ \prime} \) (b) \( 36^{\circ} \) (c) \( 45^{\circ} \). (d) none of these..

Below are the step‐by‐step solutions: 6. A cricket ball has a mass of 160 gm, which is 0.16 kg. Its kinetic energy (KE) is given by   KE = (1/2) m v². Substitute m = 0.16 kg and v = 22 m/s:   KE = 0.5 × 0.16 × (22²) = 0.08 × 484 = 38.72 J. Answer: (d) 38.72 J. 7. Friction is the resistive force encountered when two surfaces slide past each other. In options (a), (b), and (c) the surfaces in contact are sliding or being pushed along another surface. Lifting a heavy object (option (d)) involves overcoming gravitational force, not friction between surfaces. Answer: (d) A person lifting a heavy object. 8. The relation between torque (τ), moment of inertia (I), and angular acceleration (α) is:   τ = I α ⟹ α = τ / I. Here, I = 100 kg·m² and τ = 50 N·m, so:   α = 50 / 100 = 0.5 rad/s². Answer: (d) 0.5 rad/s². 9. Capillary rise (h) is inversely proportional to the radius (r) of the tube (h ∝ 1/r). If the initial capillary rise is 29.4 cm at a certain radius, then doubling the tube radius will halve the capillary rise:   New h = 29.4 cm / 2 = 14.7 cm. Answer: (a) 14.7 cm. 10. Temperature differences in Celsius and Kelvin are numerically identical because 1°C difference = 1 K difference. Therefore, a 15°C difference is also a 15 K difference. Since none of the options (27°, 36°, 45°) equal 15, the correct answer is: Answer: (d) none of these. Thus, the answers are: 6. (d) 7. (d) 8. (d) 9. (a) 10. (d)