State the hypotheses and identily the daim with the correct hypothesis. \[ \begin{array}{l} H_{0}=\mu=8.5 \text { not daim } \quad \text { т } \\ H_{1}=\mu \geqslant 8.5 \text { daim } \quad \text {, } \end{array} \] This hypothesis test is a \( \square \) two-tailed test. Fart: \( 1 / 5 \) Part 2 of 5 Find the critical value(s). Round the answer to at least two decimal places. If there is more than one critical value, separate them with commas. Qitical value(s): \( \square \) \( \pm \square \) Skip Part Chack Save For Later 8

In hypothesis testing, the null hypothesis \(H_0\) represents a statement of no effect or no difference, while the alternative hypothesis \(H_1\) represents what you are trying to prove. In your scenario, you are testing whether the true population mean is greater than or equal to 8.5, which leads us to a one-tailed test, not a two-tailed test as suggested by the prompt. To find the critical value, you would typically refer to the z-table or t-table (depending on sample size) using your significance level (commonly 0.05 for a 95% confidence level). For a one-tailed test at a significance level of 0.05, the critical z-value is approximately 1.645, indicating the cutoff for rejecting \(H_0\) in favor of \(H_1\). Thus, the critical value(s) would be \( \pm 1.645 \).