Write the polynomial as a product of linear factors \( x^{3}+5 x^{2}-9 x-45 \) \( (x-[?])(x+3)(x+[\quad]) \)

Factor the expression by following steps: - step0: Factor: \(x^{3}+5x^{2}-9x-45\) - step1: Rewrite the expression: \(x^{2}\times x+x^{2}\times 5-9x-9\times 5\) - step2: Factor the expression: \(x^{2}\left(x+5\right)-9\left(x+5\right)\) - step3: Factor the expression: \(\left(x^{2}-9\right)\left(x+5\right)\) - step4: Factor the expression: \(\left(x-3\right)\left(x+3\right)\left(x+5\right)\) To express the polynomial \( x^{3}+5 x^{2}-9 x-45 \) as a product of linear factors, we can factor it as follows: \[ x^{3}+5 x^{2}-9 x-45 = (x-3)(x+3)(x+5) \] Thus, the polynomial can be written in the form: \[ (x-3)(x+3)(x+5) \] So, the missing values in your expression are: - The first factor is \( x-3 \) - The second factor is \( x+3 \) - The third factor is \( x+5 \) Therefore, the complete expression is: \[ (x-3)(x+3)(x+5) \]