lord of the fies quotes - chap: Clever | Portal Unit 6 : Systems of Linear Eo nation/coursework/16721/f3121614-d3e7-3c22-a014-b1468914b842/TY e to Renais.. Ceremony \( \mid \) Definiti_ Dictionary by Merria, 1-Ready Freckle Student Das Play Kahootl - Enter Coursework EdgeXL On-Ramp Wall Test Yourselfl practice tool Yochanan walked from home to the bus stop at an average speed of 5 mph . He immediately got on his school bus and traveled at an average speed of 60 mph until he got to school. The total distance from his home to school is 35 miles, and the entire trip took 1.5 hours. The following system of equations represents this: \( 5 x+60 y=35 \) \[ x+y=1.5 \] Yochanan walked how many miles? \( \square \) Next Sign out Feb 26 7:26 US

To solve the problem, we need to determine how many miles Yochanan walked. We have the following system of equations: 1. \( 5x + 60y = 35 \) (Equation 1) 2. \( x + y = 1.5 \) (Equation 2) Where: - \( x \) is the time (in hours) Yochanan walked. - \( y \) is the time (in hours) he spent on the bus. ### Step 1: Solve the system of equations We can solve these equations simultaneously. Let's start with Equation 2 to express \( y \) in terms of \( x \): \[ y = 1.5 - x \] ### Step 2: Substitute \( y \) into Equation 1 Now, we substitute \( y \) into Equation 1: \[ 5x + 60(1.5 - x) = 35 \] ### Step 3: Simplify the equation Now, let's simplify this equation: \[ 5x + 90 - 60x = 35 \] Combine like terms: \[ -55x + 90 = 35 \] ### Step 4: Solve for \( x \) Now, isolate \( x \): \[ -55x = 35 - 90 \] \[ -55x = -55 \] \[ x = 1 \] ### Step 5: Find \( y \) Now that we have \( x \), we can find \( y \): \[ y = 1.5 - x = 1.5 - 1 = 0.5 \] ### Step 6: Calculate the distance walked Now, we can calculate the distance Yochanan walked. Since he walked for \( x \) hours at a speed of 5 mph, the distance \( d \) he walked is: \[ d = 5x = 5(1) = 5 \text{ miles} \] ### Final Answer Yochanan walked **5 miles**.