Solve the inequality \( 9 x+2<8 x-3 \). Write the solution set in interval notation, and graph it. The solution set is \( \square \). (Type your answer in interval notation.)

To solve the inequality \( 9x + 2 < 8x - 3 \), we can start by isolating \( x \). Subtract \( 8x \) from both sides: \[ 9x - 8x + 2 < -3 \] \[ x + 2 < -3 \] Next, we subtract 2 from both sides: \[ x < -5 \] The solution set in interval notation is \( (-\infty, -5) \). To graph this solution, you would draw a number line with an open circle at -5 (indicating -5 is not included) and shade the line to the left, indicating all values less than -5 are included in the solution set.