S10) Solve the linear equation below. \[ 6 x-9=2(2 x+8) \]

г) \( \log _{2}(x-2)^{2}+\log _{\sqrt{2}} x=6 \)

4.2 Homework \[ \begin{array}{l}\text { Factor } f(x) \text { into linear factors given that } k \text { is a zero of } f(x) \text {. } \\ f(x)=3 x^{3}+13 x^{2}-118 x+72 ; k=4 \\ f(x)=\square \text { (Factor completely.) }\end{array} \]

В) \( \log _{5}^{2}(2 x)-20 \log _{5}(2 x)=21 \).

Factor \( f(x)=2 x^{3}+9 x^{2}-51 x+40 \) into linear factors given that -8 is a zero of \( f(x) \). \( f(x)=2 x^{3}+9 x^{2}-51 x+40=\square \) \( ( \) Factor completely.)

Divide the expression. \( \frac{3 x^{4}-7 x^{3}+6 x-18}{3 x-7} \) \( \frac{3 x^{4}-7 x^{3}+6 x-18}{3 x}=\square \) (Simplify your answer.)