Lynn, Jude, and Anne were given the function \( f(x)=-2 x^{2}+32 \), and they were asked to find \( f(3) \) Lynn's answer was 14, Jude's answer was 4 , and Anne's answer was \( \pm 4 \). Who is correct?

Factor \( f(x)=2 x^{3}+9 x^{2}-51 x+40 \) into linear factors given that -8 is a zero of \( f(x) \). \( f(x)=2 x^{3}+9 x^{2}-51 x+40=\square \) \( ( \) Factor completely.)

Divide the expression. \[ \begin{array}{l}\frac{3 x^{4}-7 x^{3}+6 x-18}{3 x-7} \\ \frac{3 x^{4}-7 x^{3}+6 x-18}{3 x-7}=\square(\text { Simplify your answer. })\end{array} \]

Divide the expression. \( \frac{3 x^{4}-7 x^{3}+6 x-18}{3 x-7} \) \( \frac{3 x^{4}-7 x^{3}+6 x-18}{3 x}=\square \) (Simplify your answer.)

Divide the expression. \( \frac{6 x^{4}-2 x^{2}+6}{x^{2}+2} \) \( \frac{6 x^{4}-2 x^{2}+6}{x^{2}+2}=\square \) (Simplify your answer.)

Determina per quare valore di a la funzlone \( y=\frac{x}{a-x} \) ha dominio \( D: x \neq-2 \). \( P(2 ; 5) \). \[ [a=8, b=2 \mid \]