Suppose that \( \$ 10,970 \) is invested at an interest rate of \( 5.5 \% \) per year, compounded continuously. a) Find the exponential function that describes the amount in the account after time \( t \), in years. b) What is the balance after 1 year? 2 years? 5 years? 10 years? c) What is the doubling time? a) The exponential growth function is \( \mathrm{P}(\mathrm{t})=10970 e^{0.055 t} \). (Type exponential notation with positive exponents. Do not simplify. Use integers or decimals for any numbers in the equation.) b) The balance after 1 year is \( \$ 11,590.25 \). (Simplify your answers. Round to two decimal places as needed.) The balance after 2 years is \( \$ \square \). (Simplify your answers. Round to two decimal places as needed.)

Quais são as vantagens de participar de um consórcio? \( \begin{array}{ll}\square & \text { A) Possibilidade de comprar bens sem pagar juros. } \\ \square & \text { B) Possibilidade de contemplação antecipada. } \\ \begin{array}{ll}\text { D) Aquisção imediata do bem. }\end{array}\end{array} \)

En una empresa, el índice de rentabilidad ( \( r \) ) de un proyecto está dado por: \[ r=5 \cdot \log \left(\frac{t}{i}\right) \] Donde \( i \) es el dinero invertido en el proyecto y \( t \) es el dinero recibido al final del proyecto. Si para el proyecto se invierte \( \$ 1000000 \) y se obtiene una rentabilidad igual a 5 , ¿qué expresión permite determinar el dinero \( t \) que se recibirá al finalizar el proyecto? A) \( 6=5 \cdot \log t+30 \) B) \( 6=5 \cdot \log t-11 \) C) \( 6=5 \cdot \log t-25 \) D) \( 6=5 \cdot \log t-30 \)

A quel pourcentage de réduction correspond le coefficient multiplicateur 0,25 ?

The price of a cell phone is \( \$ 700 \) plus UAT of 10 i Calculate the total cost of the phone.

A man borrowed \( \$ 10,000 \) from the bank for 3 years at \( 12 \% \) per annum. Calculate the interest he is charged amount of the loan.