Triangle \( P Q R \) has a right angle at \( Q \). \( P Q=3.4 \mathrm{~cm} \) and \( P R=5.8 \mathrm{~cm} \). Work out the size of angle \( Q R P \). Give your answer correct to 1 decimal place.

\( \cos r x - \cos x + 1 = \)

\( \left. \begin{array} { l } { \frac { \operatorname { Arctan } ( \tan ( 5 ) ) } { \operatorname { Sen } ( \operatorname { arcsen } ( 5 ) ) } + \operatorname { Tan } \{ \operatorname { Cos } ( \operatorname { Cos } ^ { - 1 } ( x ) ) \} = - 0.7 } \\ { 16 ^ { \circ } } \\ { - 12 ^ { \circ } } \\ { - 8 ^ { \circ } } \\ { 4 ^ { \circ } } \end{array} \right. \)

\( \cos ^ { r } x - \sin x = \frac { 1 } { r } \)

\( g ( x ) = \cos ( x ) - \sin ( x ) = 0 \)

\( \cos ^ { r } x - \sin x = \frac { 1 } { r } \)