Chaper Review 6.1 Exponent Laws, pages \( 342-351 \) 1. Simplify, then evaluate. Give your answer as a whole number or a fraction. a) \( 6^{-5} \div 6^{-3} \) b) \( 5^{-3} \times 5^{2} \times 5^{4} \)

\( 1 \leftarrow \) Show that \( A I=I A=A \). \( A=\left[\begin{array}{rr}1 & 8 \\ -2 & 2\end{array}\right] \)

Three-fifths of Jesse Black's inventory was destroyed by fire. He sold the remaining part, which was slightly damaged, for two-thirds of its value and received \( \$ 3400 \). (a) What was the value of the destroyed part of the inventory? (b) What was the value of the inventory before the fire? (a) The value is \( \$ \square \). (Round to the nearest cent as needed.)

\( 1 \leftarrow \quad \) Determine whether \( B \) is the inverse of \( A \). \( A=\left[\begin{array}{rr}3 & -7 \\ -2 & 5\end{array}\right], \quad B=\left[\begin{array}{ll}5 & 7 \\ 2 & 3\end{array}\right] \)

Rewrite the following without an exponent \[ (-7)^{-2} \]

a) \( x+y=2 \) b) \( x+x-y=4+y \)