Factor $$ P(x) $$ into linear factors given that $$ k $$ is a zero of $$ P $$. $$ P(x)=x^{3}-2 x^{2}-7 x-4 ; k=-1 $$ $$ x^{3}-2 x^{2}-7 x-4=\square $$ (Type your answer in factored form.)

Question

Gibbs Boone · Accepted Answer

$$ x^3 - 2x^2 - 7x - 4 = (x + 1)^2(x - 4) $$

Factor \( P(x) \) into linear factors given that \( k \) is a zero of \( P \). \( P(x)=x^{3}-2 x^{2}-7 x-4 ; k=-1 \) \( x^{3}-2 x^{2}-7 x-4=\square \) (Type your answer in factored form.)

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Factor \( P(x) \) into linear factors given that \( k \) is a zero of \( P \). \( P(x)=x^{3}-2 x^{2}-7 x-4 ; k=-1 \) \( x^{3}-2 x^{2}-7 x-4=\square \) (Type your answer in factored form.)

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