( 7 equation expresses a linear relationship between a response variable y and two or more predictor variables.

Factor \( P(x) \) into linear factors given that \( k \) is a zero of \( P \). \( P(x)=x^{3}-2 x^{2}-7 x-4 ; k=-1 \) \( x^{3}-2 x^{2}-7 x-4=\square \) (Type your answer in factored form.)

Factor \( f(x)=2 x^{3}+9 x^{2}-51 x+40 \) into linear factors given that -8 is a zero of \( f(x) \). \( f(x)=2 x^{3}+9 x^{2}-51 x+40=\square \) \( ( \) Factor completely.)

Divide the expression. \[ \begin{array}{l}\frac{3 x^{4}-7 x^{3}+6 x-18}{3 x-7} \\ \frac{3 x^{4}-7 x^{3}+6 x-18}{3 x-7}=\square(\text { Simplify your answer. })\end{array} \]

В) \( \log _{5}^{2}(2 x)-20 \log _{5}(2 x)=21 \).

Divide the expression. \( \frac{3 x^{4}-7 x^{3}+6 x-18}{3 x-7} \) \( \frac{3 x^{4}-7 x^{3}+6 x-18}{3 x}=\square \) (Simplify your answer.)