Ten grams ( 10 g ) of an impure sample of sodium carbonate is added to \( 100 \mathrm{~cm}^{3} \) of a 0,2 mol \( \mathrm{dm}^{3} \) solution of hydrochloric acid. The acid is in excess. The equation for the reaction is: \( \mathrm{Na}_{2} \mathrm{CO}_{3}+\mathrm{HCl} \rightarrow \mathrm{NaCl}+\mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2} \) \( 8.3 .1 \quad \) Balance the equation above. \( 8.3 .2 \quad \) Calculate the number of moles of hydrochloric acid. The excess acid neutralises \( 20 \mathrm{~cm}^{3} \) of a solution of 0,1 mol.dm of magnesium hydroxide. \( 2 \mathrm{HCl}(\mathrm{aq})+\mathrm{Mg}(\mathrm{OH})_{2}(\mathrm{aq}) \rightarrow \mathrm{MgCl}_{2} \) (aq) \( +\mathrm{H}_{2} \mathrm{O}(t) \)
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