(C) $$ -\frac{\pi}{3} $$ 2. (3 points) If $$ x \in[0, \pi] $$, at which does the function $$ y=\pi^{2}-\sin (x) $$ have horizontal tangent lines? $$ \begin{array}{ll} ext { A) } x=\frac{\pi}{4} & ext { (B) } x=\frac{\pi}{6} \ ext { (C) } x=\frac{\pi}{2} & ext { D } x=0, \pi\end{array} $$

Question

(C) $$ -\frac{\pi}{3} $$ 2. (3 points) If $$ x \in[0, \pi] $$, at which does the function $$ y=\pi^{2}-\sin (x) $$ have horizontal tangent lines? $$ \begin{array}{ll}	ext { A) } x=\frac{\pi}{4} & 	ext { (B) } x=\frac{\pi}{6} \ 	ext { (C) } x=\frac{\pi}{2} & 	ext { D } x=0, \pi\end{array} $$

Cruz Chan · Accepted Answer

The function $$ y = \pi^2 - \sin(x) $$ has a horizontal tangent line at $$ x = \frac{\pi}{2} $$.

(C) \( -\frac{\pi}{3} \) 2. (3 points) If \( x \in[0, \pi] \), at which does the function \( y=\pi^{2}-\sin (x) \) have horizontal tangent lines? \( \begin{array}{ll}\text { A) } x=\frac{\pi}{4} & \text { (B) } x=\frac{\pi}{6} \\ \text { (C) } x=\frac{\pi}{2} & \text { D } x=0, \pi\end{array} \)

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(C) \( -\frac{\pi}{3} \) 2. (3 points) If \( x \in[0, \pi] \), at which does the function \( y=\pi^{2}-\sin (x) \) have horizontal tangent lines? \( \begin{array}{ll}\text { A) } x=\frac{\pi}{4} & \text { (B) } x=\frac{\pi}{6} \\ \text { (C) } x=\frac{\pi}{2} & \text { D } x=0, \pi\end{array} \)

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