(9) $$ 8 a_{4}=2 a_{15}, a_{3}^{2}=2 a_{11} $$ $$ \begin{array}{ll} ext { c) } a_{3} \cdot a_{5}=-21, a_{5} \cdot a_{7}=39 & ext { b) } a_{3} \cdot a_{4}=77, a_{2}+a_{3}+a_{4}=21 \ ext { e) } a_{2} \cdot a_{5}=-5, a_{3} \cdot a_{4}=3 & ext { d) } a_{1} \cdot a_{4}=58, a_{1}+a_{2}+a_{3}+a_{4}=62 \ a_{1}^{2}+a_{8}^{2}=400, a_{7}+a_{8}+a_{10}=-4\end{array} $$

Question

(9) $$ 8 a_{4}=2 a_{15}, a_{3}^{2}=2 a_{11} $$ $$ \begin{array}{ll}	ext { c) } a_{3} \cdot a_{5}=-21, a_{5} \cdot a_{7}=39 & 	ext { b) } a_{3} \cdot a_{4}=77, a_{2}+a_{3}+a_{4}=21 \ 	ext { e) } a_{2} \cdot a_{5}=-5, a_{3} \cdot a_{4}=3 & 	ext { d) } a_{1} \cdot a_{4}=58, a_{1}+a_{2}+a_{3}+a_{4}=62 \ a_{1}^{2}+a_{8}^{2}=400, a_{7}+a_{8}+a_{10}=-4\end{array} $$

Perkins Elliott · Accepted Answer

Nakon računanja, pronađena je vrijednost $$ a_{3} = 54.5 $$. Slijedi računanje ostalih vrijednosti i provjera jednadžbi.

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