Peterson Fernandez

09/26/2023 · Elementary School

tinúa con el ejercicio de cramer \[ x=\frac{\left|\begin{array}{ll}5 & 3 \\ 27 & 7\end{array}\right|}{\left|\begin{array}{ll}5 & 3 \\ 4 & 7\end{array}\right|}=\frac{(5)(7)-(27)(3)}{(5)(7)-(4)(3)} \Rightarrow \frac{35-81}{35-12}= \] \( \begin{array}{l}a_{1} x+b_{1} y=c_{1} \\ a_{2} x+b_{2} y=c_{2}\end{array} \) \( \begin{array}{l}x+3 y=5 \\ x+7 y=27\end{array} \)