Given the function: $$ y=\frac{x+5}{x^{2}-4} $$ a) Determine $$ y $$ if $$ x=0 $$ b) Determine $$ x $$ if $$ y=0 $$ c) Which value of $$ x $$ is not permissible? Give a reason for your answer. Use the dual-intercept method to sketch graph the function $$ -x=3-y $$ On a set of axes map the graphs defined by $$ \{(x ; y) \mid x

Question

Given the function: $$ y=\frac{x+5}{x^{2}-4} $$ a) Determine $$ y $$ if $$ x=0 $$ b) Determine $$ x $$ if $$ y=0 $$ c) Which value of $$ x $$ is not permissible? Give a reason for your answer. Use the dual-intercept method to sketch graph the function $$ -x=3-y $$ On a set of axes map the graphs defined by $$ \{(x ; y) \mid x<2\} $$ and $$ \{(x ; y) \mid y \geq-1\} $$ NOTE:- Use the graph paper provided

Reyes Simpson · Accepted Answer

a) When $$ x = 0 $$, $$ y = -\frac{5}{4} $$. b) When $$ y = 0 $$, $$ x = -5 $$. c) The not permissible values of $$ x $$ are $$ x = 2 $$ and $$ x = -2 $$ because they make the denominator zero. The graph of $$ -x = 3 - y $$ has intercepts at (0, 3) and (-3, 0). The region for $$ x < 2 $$ is to the left of the vertical line at $$ x = 2 $$, and the region for $$ y \geq -1 $$ is above the horizontal line at $$ y = -1 $$.

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