The murder of Alexander Litvinenko, a Russian dissident, was thought to be by poisoning from the rare and highly radioactive element polonium- 210 ( \( { }^{210} \) Po). The half-life of \( { }^{210} \) Po is 138.4 yr . If 0.8 mg of \( { }^{210} \) Po is present in a sample, then \( A(t)=0.8\left(\frac{1}{2}\right)^{\frac{t}{138.4}} \), gives the amount \( A(t) \) (in mg ) present after \( t \) years. Evaluate the function for the given values of \( t \) and interpret the meaning in context. Round to 3 decimal places if necessary. Part 1 of 3 (a) \( A(138.4)=\square \) This means that after \( \square \) years, the amount of \( { }^{210} \mathrm{Po} \) is \( \square \mathrm{in} \mathrm{mg} \).
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