You are on the Mathematics Knowledge section. Q: Solve for \( z: 3 z-5+2 z=25-5 z \)

tinúa con el ejercicio de cramer \[ x=\frac{\left|\begin{array}{ll}5 & 3 \\ 27 & 7\end{array}\right|}{\left|\begin{array}{ll}5 & 3 \\ 4 & 7\end{array}\right|}=\frac{(5)(7)-(27)(3)}{(5)(7)-(4)(3)} \Rightarrow \frac{35-81}{35-12}= \] \( \begin{array}{l}a_{1} x+b_{1} y=c_{1} \\ a_{2} x+b_{2} y=c_{2}\end{array} \) \( \begin{array}{l}x+3 y=5 \\ x+7 y=27\end{array} \)

Question 5 - of 19 step 1 of 1 \( z \) varies directly as the cube of \( x \) and inversely as \( y \). If \( z=237 \) when \( x=10 \) and \( y=2 \), find \( z \) if \( x=8 \) and \( y=3 \). Round your answer to two decimal places if necessary.

Determine the implied domain of the following function. Express your answer in interval notation. \[ g(x)=-3 x+2 \] \[ \]

2 varies directly as the cube of \( x \) and inversely as \( y \). If \( z=237 \) when \( x=10 \) and \( y=2 \), find \( z \) if \( x=8 \) and Round your answer to two decimal places if necessary.

\( \left. \begin{array} { l } { - x + y = 3 } \\ { y = 3 - x } \\ { y = x - 3 } \end{array} \right. \)