Question
6 from Unit 6, Lesson 4 Solve each equation. \( a-2.01=5.5 \) \[ b+2.01=5.5 \] \( 10 c=13.71 \)
Ask by Frank Barker. in the United States
Feb 25,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
a = 7.51, b = 3.49, c = 1.371
Solution
Let's solve each equation step by step.
1. Equation: a - 2.01 = 5.5
To isolate a, add 2.01 to both sides:
a = 5.5 + 2.01 = 7.51
2. Equation: b + 2.01 = 5.5
To isolate b, subtract 2.01 from both sides:
b = 5.5 - 2.01 = 3.49
3. Equation: 10c = 13.71
To solve for c, divide both sides by 10:
c = 13.71 / 10 = 1.371
So, the solutions are:
a = 7.51, b = 3.49, and c = 1.371.
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Beyond the Answer
To solve the first equation \( a - 2.01 = 5.5 \), you can isolate \( a \) by adding 2.01 to both sides. This gives you \( a = 5.5 + 2.01 = 7.51 \). Next, for the second equation \( b + 2.01 = 5.5 \), subtract 2.01 from both sides to find \( b \). So, \( b = 5.5 - 2.01 = 3.49 \). Finally, solve the equation \( 10c = 13.71 \) by dividing both sides by 10. You find that \( c = 13.71 / 10 = 1.371 \).