Question
Evaluate: \( b^{2}-4 a c \) where \( a=-5, b=0 \) and \( c=3 \)
Ask by Valdez Craig. in the United States
Feb 27,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
\( b^{2}-4ac = 0 - 4*(-5)*3 = 0 + 60 = 60 \)
Solution
Substitute \( a=-5,b=0,c=3 \) into the expression \( b^{2}-4ac \).
Evaluate the expression by following steps:
- step0: Evaluate:
\(b^{2}-4ac\)
- step1: Substitute:
\(0^{2}-4\left(-5\right)\times 3\)
- step2: Calculate:
\(0-4\left(-5\right)\times 3\)
- step3: Multiply:
\(0+60\)
- step4: Remove 0:
\(60\)
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Simplify this solution Bonus Knowledge
Let's plug in the values of \( a \), \( b \), and \( c \) into the expression \( b^{2}-4 a c \): 1. First, calculate \( b^{2} \): \[ b^{2} = 0^{2} = 0 \] 2. Next, calculate \( -4 a c \): \[ -4 a c = -4 \times (-5) \times 3 \] \[ = 20 \times 3 = 60 \] 3. Finally, substitute these results back into the expression: \[ b^{2} - 4 a c = 0 - 60 = -60 \] So, the evaluation of \( b^{2}-4 a c \) where \( a=-5, b=0 \) and \( c=3 \) is \(-60\).
