$$ 3 x+4 y \div 2 $$ for $$ x=7 $$ and $$ y=10 $$

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Evaluate the expression by following steps:
- step0: Evaluate:
  $$3x+4y\div 2$$
- step1: Substitute:
  $$3\times 7+4\times 10\div 2$$
- step2: Multiply the numbers:
  $$21+4\times 10\div 2$$
- step3: Multiply the numbers:
  $$21+40\div 2$$
- step4: Divide the numbers:
  $$21+20$$
- step5: Add the numbers:
  $$41$$
To evaluate the expression $$ 3x + 4y \div 2 $$ for $$ x = 7 $$ and $$ y = 10 $$, we follow these steps:

1. Substitute the values of $$ x $$ and $$ y $$ into the expression:
   $$
   3(7) + 4(10) \div 2
   $$

2. Calculate $$ 3(7) $$:
   $$
   3(7) = 21
   $$

3. Calculate $$ 4(10) $$:
   $$
   4(10) = 40
   $$

4. Now, substitute these values back into the expression:
   $$
   21 + 40 \div 2
   $$

5. Perform the division $$ 40 \div 2 $$:
   $$
   40 \div 2 = 20
   $$

6. Finally, add $$ 21 + 20 $$:
   $$
   21 + 20 = 41
   $$

Thus, the result of the expression is $$ 41 $$.
The result of the expression $$ 3x + 4y \div 2 $$ when $$ x = 7 $$ and $$ y = 10 $$ is 41.

\( 3 x+4 y \div 2 \) for \( x=7 \) and \( y=10 \)

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