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\begin{tabular}{|l|l|l|}\hline Write each equation in slope-intercept form. \\ \hline 7. \( x+y=6 \) & 8. \( 5 x+2 y=-2 \) & 9. \( 2 x-4 y=28 \) \\ & & \\ \hline\end{tabular}

Ask by Carlson Frazier. in Guam
Feb 24,2025

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Answer

The equations in slope-intercept form are: 7. \( y = -x + 6 \) 8. \( y = -\frac{5}{2}x - 1 \) 9. \( y = \frac{1}{2}x - 7 \)

Solution

We want to rewrite each equation in slope-intercept form, y = mx + b. For equation 7:  x + y = 6 Subtract x from both sides:  y = –x + 6 For equation 8:  5x + 2y = –2 Subtract 5x from both sides:  2y = –5x – 2 Divide both sides by 2:  y = –(5/2)x – 1 For equation 9:  2x – 4y = 28 Subtract 2x from both sides:  –4y = –2x + 28 Divide both sides by –4:  y = (2/4)x – 7 Simplify (2/4) to (1/2):  y = (1/2)x – 7 Thus, the equations in slope-intercept form are:  7. y = –x + 6  8. y = –(5/2)x – 1  9. y = (1/2)x – 7

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To convert each equation into slope-intercept form (y = mx + b), we isolate y on one side. For the first equation: 1. \( x + y = 6 \) - Subtract \( x \) from both sides: - \( y = -x + 6 \) For the second equation: 2. \( 5x + 2y = -2 \) - Subtract \( 5x \) from both sides: - \( 2y = -5x - 2 \) - Divide everything by 2: - \( y = -\frac{5}{2}x - 1 \) For the third equation: 3. \( 2x - 4y = 28 \) - Subtract \( 2x \) from both sides: - \( -4y = -2x + 28 \) - Divide everything by -4: - \( y = \frac{1}{2}x - 7 \) Thus, the equations in slope-intercept form are: 1. \( y = -x + 6 \) 2. \( y = -\frac{5}{2}x - 1 \) 3. \( y = \frac{1}{2}x - 7 \)

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