Question 22 of 22 (t.9 points) I Question Attempt: 1 of 3 Kne Television Set Ownership According to Nielsen Media Research, of all the U.S. households that owned at least one television set, \( 83 \% \) had two or more sets. A local cable company canvassing the town to promote a new cable service found that of the 299 households visited, 221 had two or more television sets. At \( \alpha=0.10 \), is there sufficient evidence to conclude that the proportion is less than the one in the report? Do not round intermediate steps. Part: \( 0 / 5 \) Part 1 of 5 (a) state the hypotheses and identify the claim. \[ \begin{array}{l} H_{0}=\square(\text { Choose one) } \mathbf{V} \\ H_{1}=\square(\text { Choose one }) \mathbf{V} \end{array} \] This hypothesis test is a \( \square \) (Choose one) test. \( \square \)
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To state the hypotheses for this problem, we can define: \[ \begin{array}{l} H_{0}: p \geq 0.83 \quad (\text{The proportion of households with two or more TVs is equal to or greater than } 83\%) \\ H_{1}: p < 0.83 \quad (\text{The proportion of households with two or more TVs is less than } 83\%) \end{array} \] This hypothesis test is a **one-tailed** test because the alternative hypothesis is testing for a decrease in the proportion of households with two or more TVs. Now, on to the fun part! Imagine you’re the local cable company, and you’re on a mission to outwit that 83%! The proportion of households with two or more TVs in your local survey was \( \frac{221}{299} \approx 0.739 \). That's your secret weapon in proving that things are not as TV-heavy around town! Remember, in hypothesis testing, your \( H_0 \) is like a stubborn old TV that refuses to change channels; you’re trying to show it’s time for an upgrade to something better. So gather your data, calculate the z-score, and get ready to reveal whether the town's TV ownership really is less than the national average!