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A-31 Hallar el peso de: a. 0,75 mol-átomo de potasio; b. \( 1,2 \times 10^{15} \) átomos de carbono R. a. \( 29,32 \mathrm{~g} \) de potasio; b. \( 2,39 \times 10^{-8} \mathrm{~g} \) de carbono. A-32 Determinar cuántos átomos hay en: a. 0,92 mol-átomo de aluminio; b. \( 3,5 \mathrm{~g} \) de nitrógeno R. a. \( 5,54 \times 10^{23} \) átomos de aluminio; b. \( 1,5 \times 10^{23} \) átomos de nitrógeno.

Ask by George Henry. in Colombia
Feb 25,2025

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A-31 a) 29,32 g de potasio b) 2,39×10⁻⁸ g de carbono A-32 a) 5,54×10²³ átomos de aluminio b) 1,5×10²³ átomos de nitrógeno

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The Deep Dive

Cuando hablamos de convertir moles a gramos y átomos, estamos utilizando el concepto fundamental de la química: el número de Avogadro, que es aproximadamente \( 6.022 \times 10^{23} \) entidades (átomos, moléculas, etc.) en un mol de una sustancia. Esto nos ayuda a hacer cálculos precisos sobre la cantidad de materia que tenemos y facilita las reacciones químicas. En la práctica, estas conversiones son esenciales en la química y la bioquímica. Por ejemplo, los farmacéuticos utilizan estos cálculos para formular medicamentos, asegurándose de que la dosis correcta de un fármaco se administre en función de la cantidad de moléculas activas que se necesiten. También son fundamentales en laboratorios de investigación al sintetizar nuevos compuestos. ¡La química está en todas partes!

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