\begin{tabular}{l} Question \\ A deck of cards contains RED cards numbered \( 1,2,3,4,5 \) and BLUE cards numbered 1,2 . Let \( R \) be the event of drawing a \\ red card, \( B \) the event of drawing a blue card, \( E \) the event of drawing an even numbered card, and \( O \) the event of drawing \\ an odd card. \\ Drawing the Red 1 is one outcome of which of the following events? Select all correct answers. \\ Select all that apply: \\ B AND \( O \) \\ \( \square B \) OR \( E \) \\ \( \square B \) OR \( O \) \\ \( \square O^{\prime} \) \\ \( \square E^{\prime} \) \\ \( \square R \) AND \( E \) \\ \hline\end{tabular}

The Red 1 is an odd card, so it will certainly fall under the event of drawing an odd card \( O \). However, it is not a blue card, so it cannot be part of the event \( B \). The events \( E \) (even) and \( O \) (odd) are mutually exclusive, which means drawing Red 1 wouldn't satisfy the even condition. Now, since Red 1 is indeed a red card, it satisfies the criteria for \( R \) (red card). The event \( O' \) (not odd) and \( E' \) (not even) would not apply as Red 1 is specifically odd and not even. Overall, the correct choices would be: - \( R \) AND \( E \) - False (Red 1 is not even) - \( B \) AND \( O \) - False (Red 1 is not blue) - \( B \) OR \( E \) - False (Red 1 is not blue and is not even) - \( B \) OR \( O \) - False (Red 1 is not blue) - \( O' \) - False (because Red 1 is odd) - \( E' \) - True (because Red 1 is not even) So the “drawing the Red 1 is one outcome of” relates to: - \( O \) (odd) - \( R \) (red)