Question
15. enVision \( { }^{\ominus} \) STEM Mary saw two poison dart frogs. One was \( \frac{7}{8} \) inch long and the other was \( \frac{5}{8} \) inch long. How much longer was one than the other?
Ask by Murray Pierce. in the United States
Feb 27,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
One frog was 1/4 inch longer than the other.
Solution
To find the difference in lengths, subtract the length of the shorter frog from the longer one:
7/8 − 5/8 = (7 − 5)/8 = 2/8
Now simplify 2/8 by dividing the numerator and denominator by 2:
2/8 = 1/4
So, one frog was 1/4 inch longer than the other.
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Simplify this solution Bonus Knowledge
To find out how much longer one poison dart frog is than the other, you subtract the lengths: \( \frac{7}{8} \) inch - \( \frac{5}{8} \) inch = \( \frac{2}{8} \) inch. Simplifying \( \frac{2}{8} \), you get \( \frac{1}{4} \) inch. So, one frog is \( \frac{1}{4} \) inch longer than the other! Now, you might be wondering about the fascinating nature of poison dart frogs. Did you know that their vibrant colors act as a warning to predators about their toxicity? This incredible adaptation showcases nature’s way of balancing beauty with survival. They're small but pack a punch!
