Question 14 of 22 (2.1 points) I Question Attempt: 1 of 3 Moviegoers The average "moviegoer" sees 8.5 movies a year. A moviegoer is defined as a person who sees at least one movie in a theater in a 12 -month period. A random sample of 47 moviegoers from a large university revealed that the average number of movies seen per person was 9.6 . The population standard deviation is 3.2 movies. At the 0.05 level of significance, can it be concluded that this represents a difference from the national average? Part: \( 0 / 5 \) Part 1 of 5 State the hypotheses and identify the claim with the correct hypothesis. \[ \begin{array}{l} H_{0}: \square \text { (Choose one) } \mathbf{V} \\ H_{1}: \square \text { (Choose one) } \mathbf{V} \end{array} \] \[ \square=\square \] \[ \square \neq \square . \] This hypothesis test is a \( \square \) (Choose one) test. \( \mu \) \( \square \) > \( \square \) \( \square \)

We are investigating whether the average number of movies seen by moviegoers at this university is different from the national average (8.5 movies per year). Here’s how to set up the hypotheses: • The null hypothesis (H₀) always represents the status quo or the claim that there is no change/difference. Thus, we require that the mean number of movies is equal to the national average:   H₀: μ = 8.5 • The alternative hypothesis (H₁) represents what we are testing for – that the true mean is different. Since we are checking for “a difference” (not specifically higher or lower), this leads to:   H₁: μ ≠ 8.5 The claim that the university sample represents a difference from the national average is reflected by the alternative hypothesis, H₁. Since the alternative hypothesis is using “≠”, this is a two-tailed test. Thus, the completed statement is:  H₀: μ = 8.5    (H₀ represents the status quo)  H₁: μ ≠ 8.5    (H₁, the claim, is that there is a difference) And this is a two-tailed test.