\( x-y=2 \) \( 0.2 x+0.4 y=1 \) The \( x \)-coordinate of the solution to the system shown is 3 6

Solve the system of equations \( x-y=2;0.2x+0.4y=1 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}x-y=2\\0.2x+0.4y=1\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}x=2+y\\0.2x+0.4y=1\end{array}\right.\) - step2: Substitute the value of \(x:\) \(0.2\left(2+y\right)+0.4y=1\) - step3: Simplify: \(0.4+0.6y=1\) - step4: Move the constant to the right side: \(0.6y=1-0.4\) - step5: Subtract the numbers: \(0.6y=0.6\) - step6: Divide both sides: \(\frac{0.6y}{0.6}=\frac{0.6}{0.6}\) - step7: Divide the numbers: \(y=1\) - step8: Substitute the value of \(y:\) \(x=2+1\) - step9: Calculate: \(x=3\) - step10: Calculate: \(\left\{ \begin{array}{l}x=3\\y=1\end{array}\right.\) - step11: Check the solution: \(\left\{ \begin{array}{l}x=3\\y=1\end{array}\right.\) - step12: Rewrite: \(\left(x,y\right) = \left(3,1\right)\) The solution to the system of equations is \( x = 3 \) and \( y = 1 \). Therefore, the \( x \)-coordinate of the solution is 3.