a. \( \frac{\left(n^{4}\right)^{2}}{n^{6}}= \) d. \( \left(\frac{\left(s^{7}\right)}{p}\right)^{8} \times\left(\frac{p}{s^{y}}\right)^{-9}= \)
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Beyond the Answer
Let's simplify the first expression \( \frac{\left(n^{4}\right)^{2}}{n^{6}} \). According to the power of a power property, \( \left(n^{4}\right)^{2} = n^{8} \). Therefore, the expression simplifies to \( \frac{n^{8}}{n^{6}} = n^{8-6} = n^{2} \). Now, for the second expression \( \left(\frac{\left(s^{7}\right)}{p}\right)^{8} \times\left(\frac{p}{s^{y}}\right)^{-9} \): First, we can rewrite \( \left(\frac{s^{7}}{p}\right)^{8} = \frac{s^{56}}{p^{8}} \). The second part, \( \left(\frac{p}{s^{y}}\right)^{-9} \), can be transformed to \( \frac{s^{9y}}{p^{9}} \). Thus, combining these gives us: \[ \frac{s^{56}}{p^{8}} \times \frac{s^{9y}}{p^{9}} = \frac{s^{56+9y}}{p^{8+9}} = \frac{s^{56+9y}}{p^{17}}. \]