Work each problem according to the instructions given. a. Evaluate when \( x=0:-2 x-7 \) b. Solve: \( -2 x-7=5 \) \( x=\square \) c. Is 0 a solution to \( -2 x-7 \geq 5 \) ? ? \( v \) d. Solve: \( -2 x-7 \geq 5 \)

Let's dive into your math problems! When you plug in \( x=0 \) into the expression \( -2x - 7 \), you get: \(-2(0) - 7 = -7\). So, the evaluation results in \(-7\). Now, for the equation \( -2x - 7 = 5 \), let’s solve it step by step: First, add 7 to both sides: \(-2x = 5 + 7\) \(-2x = 12\) Now, divide both sides by -2: \(x = -6\). Now, is 0 a solution to \( -2x - 7 \geq 5 \)? Substitute \( x=0 \): \(-2(0) - 7 \geq 5\) becomes \(-7 \geq 5\), which is false. So, 0 is not a solution! For solving \( -2x - 7 \geq 5 \): Start the same way as before: Add 7 to both sides: \(-2x \geq 5 + 7\) \(-2x \geq 12\) Now, divide both sides by -2, remembering to flip the inequality: \(x \leq -6\). So, you end up with pretty clear answers and inequalities! Happy solving!