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Other than a no solution set, use interval notation to express the solution set and then graph the solution set on a number line. \( \frac{x}{3}-\frac{11}{12} \leq \frac{x}{4}+1 \) Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solution set is B. The solution set is \( \varnothing \). (Type your answer using interval notatidn.)

Ask by Mathis Collins. in the United States
Feb 26,2025

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The solution set is (-∞, 23].

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To solve the inequality \( \frac{x}{3}-\frac{11}{12} \leq \frac{x}{4}+1 \), first, we'll combine like terms. Start by eliminating the fractions by multiplying through by 12, the least common multiple of the denominators: \[ 12 \left( \frac{x}{3} \right) - 12 \left( \frac{11}{12} \right) \leq 12 \left( \frac{x}{4} \right) + 12(1) \] This simplifies to: \[ 4x - 11 \leq 3x + 12 \] Next, isolate \(x\) by subtracting \(3x\) from both sides: \[ x - 11 \leq 12 \] Then add 11 to both sides: \[ x \leq 23 \] This gives us the solution set in interval notation as \((- \infty, 23]\). To graph this on a number line, draw a line that extends infinitely to the left with a closed circle at 23, indicating that 23 is included in the solution set. So the final answer is: A. The solution set is \((- \infty, 23]\).

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phrase I. The difference between three times \( x \) and fifteen is greater than or equal to five 2. Five more than sixteen times \( x \) is less than or equal to six 3. Three more than two times \( x \) is less than seven \( \square \) 4. Five less than four times \( x \) is less than or equal to sixteen 5. Six times the sum of \( x \) and twelve is less than fourteen 6. The difference between fifteen and two times \( x \) is greater than five 7. The difference between eleven and four times \( x \) is greater than or equal to three 8. The sum of negative three times \( x \) and five is less than or equal to negative four 9. Fourteen less than five times \( x \) is at most eleven \( \qquad \) 10. Twice the sum of nine and \( x \) is greater than twenty II. Ten less than three times \( x \) is greater than eleven 12. Thirteen plus five times \( x \) is no more than thirty 13. Thirteen more than three times \( x \) is no more than the opposite of eleven 14. Half of the sum of \( x \) and six is no less than twenty 15. The difference between negative five times \( x \) and eight is greater than twelve. Solve only your inequalities! Look for your answer at the bottom. \[ \begin{array}{ll} N \quad 2 x+3 \leq 7 & E \\ C & 14-5 x \leq 11 \\ \text { C } 15-2 x>5 & \text { R } \\ F(9+x)>20 \\ E \quad 1 / 2 x+6 x \leq 30 & \text { D } \end{array} 6(x+12)<141 \] \[ \text { L } 5 x-14 \leq 11 \quad H \quad-3 x-5<-4 \] \[ \text { U } 3 x-15 \geq 5 \quad \text { A } 1 / 2(x+6) \geq 20 \] \[ E \quad 6(x-12)>14 \backslash \text { H } \quad 11-4 x \geq 3 \] \[ 3 x-10>11 \quad 0 \quad-5 x-8>12 \] \[ \vee 16 x+5<6 \quad \& \quad 3 x+13 \leq-11 \] \[ \text { Y } 4 x-5 \geq 16 \quad \text { \& } 16 x+5 \leq 6 \]
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