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Find the quotient and remainder using synthetic division. \[ \frac{x^{3}-5 x+22}{x+5} \] quotient remainder

Ask by Ortega Patel. in the United States
Feb 27,2025

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Answer

Quotient: \( x^2 - 5x + 20 \) Remainder: -78

Solution

To perform synthetic division for dividing x³ - 5x + 22 by x + 5, follow these steps: 1. Write the polynomial in standard form, including any missing terms. For x³ - 5x + 22, note that there is no x² term, so we use a coefficient of 0 for x²:   Coefficients: 1 (x³), 0 (x²), -5 (x), 22 (constant). 2. Set up synthetic division with the zero of the divisor. Since the divisor is x + 5, the zero is -5.     -5 | 1    0     -5    22        |   -5    25     -100     -------------------------        1   -5   20    -78 Steps: • Bring down the first coefficient (1). • Multiply 1 by -5, giving -5. Write this under the second coefficient (0). • Add 0 and -5 to get -5. • Multiply -5 by -5 to get 25. Write this under the third coefficient (-5). • Add -5 and 25 to get 20. • Multiply 20 by -5 to get -100. Write this under the constant term (22). • Add 22 and -100 to get -78. The bottom row gives the coefficients of the quotient and the remainder: • Quotient: x² - 5x + 20 • Remainder: -78 Therefore, the quotient is x² - 5x + 20 and the remainder is -78.

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To use synthetic division for \( \frac{x^{3}-5x+22}{x+5} \), we set \( x + 5 = 0 \) which gives us \( x = -5 \). Now we arrange the coefficients of the polynomial \( x^3 + 0x^2 - 5x + 22 \) (note that \( 0 \) is for the missing \( x^2 \) term): The coefficients are: \( 1, 0, -5, 22 \). We set up synthetic division as follows: \[ \begin{array}{r|rrrr} -5 & 1 & 0 & -5 & 22 \\ & & -5 & 25 & -100 \\ \hline & 1 & -5 & 20 & -78 \\ \end{array} \] The bottom row gives us the coefficients of the quotient and the remainder: - The quotient is \( x^2 - 5x + 20 \) (the first three numbers). - The remainder is \( -78 \) (the last number). So, the final results are: - Quotient: \( x^2 - 5x + 20 \) - Remainder: \( -78 \)

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