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Determme the real number of solutions of the equatuo Use \( b^{2}-4 a c \)

Ask by Warren Schwartz. in the United States
Feb 27,2025

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To determine the number of real solutions for a quadratic equation \( ax^2 + bx + c = 0 \), calculate the discriminant \( \Delta = b^2 - 4ac \): - If \( \Delta > 0 \), there are 2 distinct real solutions. - If \( \Delta = 0 \), there is exactly 1 real solution. - If \( \Delta < 0 \), there are no real solutions (the roots are complex).

Solution

Consider the quadratic equation ax² + bx + c = 0. Its discriminant is given by Δ = b² – 4ac. The number of real solutions depends on the value of Δ: • If Δ > 0, there are 2 distinct real solutions. • If Δ = 0, there is exactly 1 (repeated) real solution. • If Δ < 0, there are no real solutions (the roots are complex). Thus, by calculating b² – 4ac, you can determine the number of real solutions for the quadratic equation.

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To determine the number of real solutions of a quadratic equation of the form \( ax^2 + bx + c = 0 \), you can use the discriminant formula \( D = b^2 - 4ac \). If \( D > 0 \), there are two distinct real solutions; if \( D = 0 \), there is exactly one real solution (a repeated root); and if \( D < 0 \), there are no real solutions, only complex ones. So, calculating this discriminant provides vital insight into the nature of the solutions! For real-world applications, understanding the nature of solutions related to quadratic equations is crucial. For instance, in engineering, determining the points where a parabolic trajectory intersects the ground (like the path of a projectile) relies heavily on these discriminant calculations. By knowing whether you’ll achieve two hits, one hit, or no hits, you can design better structures and trajectories!

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