Question
Use the square roots property to solve the quadratic equation \( \left(9 z+\frac{1}{2}\right)^{2}+61=39 \). If there are multiple answer them separated by a comma, e.g. 1,2 . If there is no real solution, enter \( \varnothing \). Provide your answer below:
Ask by Tucker Franklin. in the United States
Feb 27,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
There is no real solution.
Solution

Sign in to Unlock Answers for Free!
A Learning Platform Trusted by Millions of Real Students and Teachers.

Answered by UpStudy AI and reviewed by a Professional Tutor
Like
Extra Insights
To solve the quadratic equation \( \left(9 z+\frac{1}{2}\right)^{2}+61=39 \), let's first isolate the squared term: \[ \left(9 z+\frac{1}{2}\right)^{2} = 39 - 61 \] This simplifies to: \[ \left(9 z+\frac{1}{2}\right)^{2} = -22 \] Since the square of a real number cannot equal a negative value, there are no real solutions. Thus, we write: \[ \varnothing \]