Solve for \( b \) : \( b-\frac{7}{4}=-\frac{2}{3} \) \( b=\square \)

To solve for \( b \), we can start by adding \(\frac{7}{4}\) to both sides of the equation: \[ b = -\frac{2}{3} + \frac{7}{4} \] Next, we need a common denominator for the fractions, which in this case is 12. Rewriting the fractions with the common denominator, we have: \[ -\frac{2}{3} = -\frac{8}{12} \] \[ \frac{7}{4} = \frac{21}{12} \] Now substitute these back into the equation: \[ b = -\frac{8}{12} + \frac{21}{12} \] Now, combine the fractions: \[ b = \frac{21 - 8}{12} = \frac{13}{12} \] Thus, the solution is: \[ b = \frac{13}{12} \]