Solve for \( y \). \( \frac{8}{4 y-24}-1=\frac{2}{y-6} \) If there is more than one solution, separate them with commas. If there is no solution, click on "No solution". \( y=\llbracket] \)
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To solve the equation \( \frac{8}{4y-24}-1=\frac{2}{y-6} \), we first simplify the left side. Notice that \( 4y - 24 = 4(y - 6) \). 1. Rewrite the equation: \[ \frac{8}{4(y-6)} - 1 = \frac{2}{y-6} \] 2. Clear the fractions by multiplying through by \( 4(y - 6) \): \[ 8 - 4(y-6) = 8 \] Expanding gives: \[ 8 - 4y + 24 = 8 \] This simplifies to: \[ -4y + 32 = 8 \] 3. Rearranging gives: \[ -4y = 8 - 32 \] \[ -4y = -24 \] \[ y = 6 \] 4. However, when substituting back \( y = 6 \) into the original equation, we find that it makes the denominator \( \frac{2}{y-6} \) undefined. Thus, \( y=6 \) is not a valid solution. Since we cannot find a valid value for \( y \), we conclude that there is no solution. So your answer is: \( y=\text{No solution} \)