13. [-/0.83 Points] DETAILS MY NOTES SCALCET9 2.XP.6.008. Find the limit. (If the limit is infinite, enter ' \( \infty \) ' or ' \( -\infty \) ', as appropriate. If the limit does not otherwise exist, enter DNI \( \lim _{x \rightarrow \infty} \frac{x^{2}}{\sqrt{x^{4}+9}} \) ASK YOUR TEA Fin
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To find the limit \( \lim_{x \rightarrow \infty} \frac{x^{2}}{\sqrt{x^{4}+9}} \), we start by simplifying the expression. As \( x \) approaches infinity, the \( 9 \) becomes negligible compared to \( x^{4} \). Thus, we can rewrite the limit as: \[ \lim_{x \rightarrow \infty} \frac{x^{2}}{\sqrt{x^{4}(1 + \frac{9}{x^{4}})}} = \lim_{x \rightarrow \infty} \frac{x^{2}}{x^{2}\sqrt{1 + \frac{9}{x^{4}}}} = \lim_{x \rightarrow \infty} \frac{1}{\sqrt{1 + \frac{9}{x^{4}}}} \] As \( x \) approaches infinity, \( \frac{9}{x^{4}} \) goes to \( 0 \), resulting in the limit evaluating to \( \frac{1}{\sqrt{1 + 0}} = 1 \). Thus, the final result is \( 1 \).