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Ravi borrowed money from a bank to buy a motorcycle. He took out a personal, amortized loan for \( \$ 18,000 \), at an interest rate of \( 5.6 \% \), with monthly payments for a term of 5 years. For each part, do not round any intermediate computations and round your final answers to the nearest cent. If necessary, refer to the list of financial formulas. (a) Find Ravi's monthly payment. (b) If Ravi pays the monthly payment each month for the full term, find his total amount to repay the loan. \( \$ \square \) (c) If Ravi pays the monthly payment each month for the full term, find the total amount of interest he will pay. \( \$ \square \)

Ask by Ross Reese. in the United States
Feb 27,2025

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(a) Ravi's monthly payment is $344.65. (b) The total amount to repay the loan is $20,679. (c) The total amount of interest Ravi will pay is $2,679.

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Beyond the Answer

To calculate the monthly payment for Ravi's loan, we can use the formula for the monthly payment of an amortized loan: \[ M = P \frac{r(1 + r)^n}{(1 + r)^n - 1} \] Where: - \( M \) is the monthly payment - \( P \) is the loan amount (\$18,000) - \( r \) is the monthly interest rate (annual rate / 12) - \( n \) is the number of total payments (loan term in months) Given: - Loan Amount, \( P = 18000 \) - Annual Interest Rate, \( 5.6\% \) or \( 0.056 \) - Monthly Interest Rate, \( r = \frac{0.056}{12} \approx 0.0046667 \) - Loan Term, \( 5 \) years or \( 5 \times 12 = 60 \) months Now substituting into the formula: \[ M = 18000 \frac{0.0046667(1 + 0.0046667)^{60}}{(1 + 0.0046667)^{60} - 1} \] Calculating \( (1 + 0.0046667)^{60} \): \[ (1 + 0.0046667)^{60} \approx 1.34871 \] Then: \[ M = 18000 \frac{0.0046667 \times 1.34871}{1.34871 - 1} \] Calculating the numerator and denominator: Numerator: \[ 0.0046667 \times 1.34871 \approx 0.0062988 \] Denominator: \[ 1.34871 - 1 \approx 0.34871 \] Now substituting back to the formula: \[ M = 18000 \frac{0.0062988}{0.34871} \approx 18000 \times 0.0180461 \approx 324.83 \] Thus, Ravi's monthly payment is approximately **\$324.83**. For the total amount to repay the loan: \[ \text{Total Repayment} = M \times n = 324.83 \times 60 \approx 19489.80 \] So, the total amount to repay the loan is approximately **\$19,489.80**. To find the total interest paid over the loan term: \[ \text{Total Interest} = \text{Total Repayment} - \text{Principal} = 19489.80 - 18000 \approx 1489.80 \] Thus, the total amount of interest he will pay is approximately **\$1,489.80**. Final Answers: (a) Monthly Payment: \( \$324.83 \) (b) Total Amount to Repay the Loan: \( \$19,489.80 \) (c) Total Amount of Interest: \( \$1,489.80 \)

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