3. $$ V_{1}^{2} x^{2}+V_{2} x^{2}=d^{2} $$ 4. $$ 5^{2}=x^{2}+4^{2} $$ 5. $$ \frac{30}{21}=2 x+ $$

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Vamos a resolver cada una de las ecuaciones que has proporcionado.

### Ecuación 3: 
$$ V_{1}^{2} x^{2} + V_{2} x^{2} = d^{2} $$

Primero, podemos factorizar $$ x^{2} $$ de la izquierda:

$$ x^{2} (V_{1}^{2} + V_{2}) = d^{2} $$

Ahora, para despejar $$ x^{2} $$:

$$ x^{2} = \frac{d^{2}}{V_{1}^{2} + V_{2}} $$

Luego, tomamos la raíz cuadrada para encontrar $$ x $$:

$$ x = \sqrt{\frac{d^{2}}{V_{1}^{2} + V_{2}}} $$

### Ecuación 4:
$$ 5^{2} = x^{2} + 4^{2} $$

Calculamos $$ 5^{2} $$ y $$ 4^{2} $$:

$$ 25 = x^{2} + 16 $$

Despejamos $$ x^{2} $$:

$$ x^{2} = 25 - 16 $$
$$ x^{2} = 9 $$

Tomamos la raíz cuadrada:

$$ x = 3 $$

### Ecuación 5:
$$ \frac{30}{21} = 2x + $$

Primero, simplificamos $$ \frac{30}{21} $$:

$$ \frac{30}{21} = \frac{10}{7} $$

Ahora, tenemos:

$$ \frac{10}{7} = 2x $$

Despejamos $$ x $$:

$$ x = \frac{10}{7 \cdot 2} $$
$$ x = \frac{10}{14} $$
$$ x = \frac{5}{7} $$

### Resumen de resultados:
1. Para la ecuación 3, $$ x = \sqrt{\frac{d^{2}}{V_{1}^{2} + V_{2}}} $$
2. Para la ecuación 4, $$ x = 3 $$
3. Para la ecuación 5, $$ x = \frac{5}{7} $$
Resolviendo las ecuaciones: 1. $$ x = \sqrt{\frac{d^{2}}{V_{1}^{2} + V_{2}}} $$ 2. $$ x = 3 $$ 3. $$ x = \frac{5}{7} $$

3. \( V_{1}^{2} x^{2}+V_{2} x^{2}=d^{2} \) 4. \( 5^{2}=x^{2}+4^{2} \) 5. \( \frac{30}{21}=2 x+ \)

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