Answer
(a) Diane's monthly payment is $368.31.
(b) Over 40 years, she will repay a total of $176,788.80.
(c) The total interest she will pay is $85,288.80.
Solution
To solve the problem, we will use the formula for the monthly payment on an amortized loan, which is given by:
\[
M = P \frac{r(1 + r)^n}{(1 + r)^n - 1}
\]
where:
- \( M \) = monthly payment
- \( P \) = principal amount (loan amount)
- \( r \) = monthly interest rate (annual interest rate divided by 12)
- \( n \) = total number of payments (loan term in months)
### Given Data:
- \( P = 91500 \)
- Annual interest rate = \( 3.75\% \) or \( 0.0375 \)
- Monthly interest rate \( r = \frac{0.0375}{12} \)
- Loan term = \( 40 \) years or \( 40 \times 12 = 480 \) months
Now, let's calculate the monthly payment \( M \).
1. Calculate the monthly interest rate \( r \):
\[
r = \frac{0.0375}{12}
\]
2. Calculate the total number of payments \( n \):
\[
n = 40 \times 12
\]
3. Substitute \( P \), \( r \), and \( n \) into the monthly payment formula.
Let's perform these calculations step by step.
### Step 1: Calculate \( r \) and \( n \)
\[
r = \frac{0.0375}{12}
\]
\[
n = 40 \times 12
\]
### Step 2: Calculate the monthly payment \( M \)
\[
M = 91500 \frac{r(1 + r)^n}{(1 + r)^n - 1}
\]
Now, I will perform these calculations.
Calculate the value by following steps:
- step0: Calculate:
\(40\times 12\)
- step1: Multiply the numbers:
\(480\)
Calculate or simplify the expression \( 0.0375/12 \).
Calculate the value by following steps:
- step0: Calculate:
\(\frac{0.0375}{12}\)
- step1: Convert the expressions:
\(\frac{\frac{3}{80}}{12}\)
- step2: Multiply by the reciprocal:
\(\frac{3}{80}\times \frac{1}{12}\)
- step3: Reduce the numbers:
\(\frac{1}{80}\times \frac{1}{4}\)
- step4: Multiply the fractions:
\(\frac{1}{80\times 4}\)
- step5: Multiply:
\(\frac{1}{320}\)
Calculate or simplify the expression \( 91500*(0.003125*(1+0.003125)^480)/((1+0.003125)^480-1) \).
Calculate the value by following steps:
- step0: Calculate:
\(\frac{91500\left(0.003125\left(1+0.003125\right)^{480}\right)}{\left(\left(1+0.003125\right)^{480}-1\right)}\)
- step1: Remove the parentheses:
\(\frac{91500\times 0.003125\left(1+0.003125\right)^{480}}{\left(1+0.003125\right)^{480}-1}\)
- step2: Add the numbers:
\(\frac{91500\times 0.003125\times 1.003125^{480}}{\left(1+0.003125\right)^{480}-1}\)
- step3: Add the numbers:
\(\frac{91500\times 0.003125\times 1.003125^{480}}{1.003125^{480}-1}\)
- step4: Convert the expressions:
\(\frac{91500\times 0.003125\left(\frac{321}{320}\right)^{480}}{1.003125^{480}-1}\)
- step5: Convert the expressions:
\(\frac{91500\times 0.003125\left(\frac{321}{320}\right)^{480}}{\left(\frac{321}{320}\right)^{480}-1}\)
- step6: Multiply:
\(\frac{\frac{183\times 321^{480}}{2^{2884}\times 5^{478}}}{\left(\frac{321}{320}\right)^{480}-1}\)
- step7: Subtract the numbers:
\(\frac{\frac{183\times 321^{480}}{2^{2884}\times 5^{478}}}{\frac{321^{480}-320^{480}}{320^{480}}}\)
- step8: Multiply by the reciprocal:
\(\frac{183\times 321^{480}}{2^{2884}\times 5^{478}}\times \frac{320^{480}}{321^{480}-320^{480}}\)
- step9: Rewrite the expression:
\(\frac{183\times 321^{480}}{2^{2884}\times 5^{478}}\times \frac{64^{480}\times 5^{480}}{321^{480}-320^{480}}\)
- step10: Rewrite the expression:
\(\frac{183\times 321^{480}}{2^{2884}\times 5^{478}}\times \frac{2^{2880}\times 5^{480}}{321^{480}-320^{480}}\)
- step11: Reduce the numbers:
\(\frac{183\times 321^{480}}{2^{4}}\times \frac{5^{2}}{321^{480}-320^{480}}\)
- step12: Multiply the fractions:
\(\frac{183\times 321^{480}\times 5^{2}}{2^{4}\left(321^{480}-320^{480}\right)}\)
- step13: Multiply:
\(\frac{4575\times 321^{480}}{16\times 321^{480}-16\times 320^{480}}\)
### Step 1: Calculate \( r \) and \( n \)
- The monthly interest rate \( r \) is approximately \( 0.003125 \).
- The total number of payments \( n \) is \( 480 \).
### Step 2: Calculate the monthly payment \( M \)
Using the formula for the monthly payment:
\[
M = 91500 \frac{0.003125(1 + 0.003125)^{480}}{(1 + 0.003125)^{480} - 1}
\]
Calculating \( M \):
\[
M \approx 368.31
\]
### (a) Monthly Payment
Diane's monthly payment is approximately **$368.31**.
### (b) Total Amount to Repay the Loan
To find the total amount to repay the loan, we multiply the monthly payment by the total number of payments:
\[
\text{Total Repayment} = M \times n
\]
Calculating this:
\[
\text{Total Repayment} = 368.31 \times 480
\]
Let's calculate this value.
Calculate the value by following steps:
- step0: Calculate:
\(368.31\times 480\)
- step1: Multiply the numbers:
\(176788.8\)
### (b) Total Amount to Repay the Loan
The total amount to repay the loan is:
\[
\text{Total Repayment} \approx 176788.80
\]
Thus, Diane's total amount to repay the loan is approximately **$176,788.80**.
### (c) Total Amount of Interest Paid
To find the total amount of interest paid, we subtract the principal from the total repayment:
\[
\text{Total Interest} = \text{Total Repayment} - P
\]
Calculating this:
\[
\text{Total Interest} = 176788.80 - 91500
\]
Let's calculate this value.
Calculate the value by following steps:
- step0: Calculate:
\(176788.8-91500\)
- step1: Subtract the numbers:
\(85288.8\)
### (c) Total Amount of Interest Paid
The total amount of interest paid is:
\[
\text{Total Interest} \approx 85288.80
\]
Thus, Diane's total amount of interest she will pay is approximately **$85,288.80**.
### Summary of Results:
- (a) Monthly Payment: **$368.31**
- (b) Total Amount to Repay the Loan: **$176,788.80**
- (c) Total Amount of Interest Paid: **$85,288.80**
Answered by UpStudy AI and reviewed by a Professional Tutor
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