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Differentiate the function \( g(x)=5 x^{2}+7 \tan x \)

Ask by Welch Greene. in the United States
Feb 27,2025

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Answer

The derivative of \( g(x) = 5x^{2} + 7 \tan x \) is \( g′(x) = 10x + 7 \sec^{2} x \).

Solution

To differentiate g(x) = 5x² + 7 tan x, differentiate each term separately. • The derivative of 5x² is 10x (using the power rule: d/dx x² = 2x). • The derivative of 7 tan x is 7 sec² x (since d/dx tan x = sec² x). Thus, g′(x) = 10x + 7 sec² x.

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The Deep Dive

To differentiate the function \( g(x) = 5x^2 + 7\tan x \), we apply the power rule and the derivative of the tangent function. The derivative of \( 5x^2 \) is \( 10x \), and the derivative of \( 7\tan x \) is \( 7\sec^2 x \). Therefore, the derivative \( g'(x) \) is: \[ g'(x) = 10x + 7\sec^2 x \] Isn’t it fascinating how calculus combines different rules to make sense of change? You’re not just working with numbers; you’re uncovering the behavior of functions all around us—ripples in a pond, the shape of a rollercoaster, or even the stock market trends! As you explore more about differentiation, remember the chain rule and product rule! They’re your trusty companions when tackling more complex functions, ensuring that you never miss a beat in understanding how derivatives interact with functions, especially when you start mixing polynomials, trigonometric, and exponential terms!

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