Point(S) possible Consider a pollitical discussion group consisting of 9 Democrets, 9 Republicans, and 3 Independents. Suppose that two group members are randomly selected, in succession, to attend a polliteal convention. Find the probabilly of selecting two Denocrats. \( \square \) (Type an integer or a simplified fraction.)

To find the probability of selecting two Democrats, we start by calculating the total number of group members, which is \(9 + 9 + 3 = 21\). For the first selection, the probability of choosing a Democrat is \(\frac{9}{21}\). Assuming the first selected member is a Democrat, there are now 8 Democrats left out of a total of 20 members. Thus, the probability of selecting a second Democrat is \(\frac{8}{20}\). Now, we multiply these probabilities together: \[ \frac{9}{21} \times \frac{8}{20} = \frac{9 \times 8}{21 \times 20} = \frac{72}{420} \] To simplify \(\frac{72}{420}\): \[ \frac{72 \div 12}{420 \div 12} = \frac{6}{35} \] Therefore, the probability of selecting two Democrats is \(\frac{6}{35}\).