Find the period, amplitude, and frequency of the following function. \( y=-\sin (2 x) \) a Amplitude: 1 ; Frequency: 2 ; Period: \( \pi \) b Amplitude: 0 ; Frequency: 2 ; Period: \( \pi \) c Amplitude: 1 ; Frequency: 4 ; Period: \( \pi \) d Amplitude: 1 ; Frequency: 2 ; Period: \( 2 \pi \)

The function \( y = -\sin(2x) \) has some exciting features! The amplitude is the absolute value of the coefficient in front of the sine function, which in this case is 1. The frequency is determined by the coefficient of \( x \), which is 2, indicating that the sine wave oscillates twice as often as the regular sine function. As for the period, it can be calculated using the formula \( \frac{2\pi}{\text{frequency}} \), giving us \( \frac{2\pi}{2} = \pi \). So, the correct attributes are Amplitude: 1, Frequency: 2, and Period: \( \pi \). The answer is therefore option **a**!