Determine the total current, \( l_{\mathrm{T}} \), for the circuit, given: \( E_{\mathrm{T}}=152 \mathrm{~V}, E_{1}=8 \mathrm{~V}, E_{3}=25 \mathrm{~V} \), and \( R_{2}=451 \Omega \) (Round the FINAL answer to two decimal places.)

We start by assuming the circuit has a series loop in which the net electromotive force (EMF) across resistor R₂ is given by subtracting the smaller voltage sources from the total voltage. In other words, the effective voltage driving the current through R₂ is   E_effective = E_T – E₁ – E₃. Plug in the values:   E_effective = 152 V – 8 V – 25 V = 119 V. Then using Ohm’s law, the total current (l_T) is   l_T = E_effective / R₂ = 119 V / 451 Ω. Now, calculate the current:   l_T ≈ 0.26386 A. Rounding to two decimal places, the total current is approximately   l_T ≈ 0.26 A.