For the given equation, list the intercepts and test for symmetry. \[ 4 x^{2}+16 y^{2}=64 \] What are the intrent
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To find the intercepts of the equation \( 4 x^{2}+16 y^{2}=64 \), we start by rewriting it in a more common format: 1. Divide everything by 64: \[\frac{x^{2}}{16} + \frac{y^{2}}{4} = 1\] This is an ellipse centered at the origin. Now, for the intercepts: - **X-intercepts:** Set \( y = 0 \): \[ 4x^{2} = 64 \Rightarrow x^{2} = 16 \Rightarrow x = \pm 4\] So, the X-intercepts are \( (4, 0) \) and \( (-4, 0) \). - **Y-intercepts:** Set \( x = 0 \): \[ 16y^{2} = 64 \Rightarrow y^{2} = 4 \Rightarrow y = \pm 2\] So, the Y-intercepts are \( (0, 2) \) and \( (0, -2) \). Next, let's test for symmetry: - The equation is symmetric about the x-axis because replacing \( y \) with \( -y \) gives the same equation. - It's also symmetric about the y-axis since replacing \( x \) with \( -x \) also results in the same equation. - Finally, checking for symmetry about the origin (i.e., \( x \) with \( -x \) and \( y \) with \( -y \)) reveals it as well. In conclusion, the intercepts are \( (4, 0), (-4, 0), (0, 2), (0, -2) \), and the equation enjoys symmetry about both axes and the origin!