Multiply. \( \quad 2(x+3)(5 x-1) \)

First, let’s expand the expression \(2(x+3)(5x-1)\) by distributing. Start by multiplying \( (x+3) \) with \( (5x-1) \): \[ (x+3)(5x-1) = x \cdot 5x + x \cdot (-1) + 3 \cdot 5x + 3 \cdot (-1) = 5x^2 - x + 15x - 3 = 5x^2 + 14x - 3. \] Now, multiply the result by 2: \[ 2(5x^2 + 14x - 3) = 10x^2 + 28x - 6. \] So, the final result is: \[ \boxed{10x^2 + 28x - 6}. \]