Question 8 of 8, Step 1 of 1 Completely factor the expression by grouping, if possible. Correct \( 8 b a-1-6 b^{2}-b \)

To factor the expression \( 8ba - 1 - 6b^2 - b \) by grouping, we can follow these steps: 1. **Rearrange the expression**: Group the terms in a way that makes it easier to factor. We can rearrange it as: \[ (8ba - 6b^2) + (-b - 1) \] 2. **Factor out common factors from each group**: - From the first group \( 8ba - 6b^2 \), we can factor out \( 2b \): \[ 2b(4a - 3b) \] - From the second group \( -b - 1 \), we can factor out \(-1\): \[ -1(b + 1) \] 3. **Combine the factored groups**: Now we have: \[ 2b(4a - 3b) - 1(b + 1) \] 4. **Check for common factors**: The expression does not have a common factor between the two groups, so we cannot factor it further. Thus, the expression \( 8ba - 1 - 6b^2 - b \) can be factored as: \[ 2b(4a - 3b) - (b + 1) \] However, it appears that this expression does not factor neatly into a product of simpler polynomials. Therefore, the final factored form is: \[ 2b(4a - 3b) - (b + 1) \] If you need further assistance or a different approach, please let me know!