Question
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12 Fill in the blanks with \( < \),\( \rangle , or = \) to correctly compare the expressions. \( \sqrt{7}+9-7+\sqrt{9} \) \( \sqrt{35}-\sqrt[3]{115} \)

Ask by Wheeler Mcfarlane. in the United States
Feb 25,2025

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Tutor-Verified Answer

Answer

√7 + 9 – 7 + √9 > √35 – ∛115

Solution

We are given two expressions to compare:   Expression 1: √7 + 9 – 7 + √9   Expression 2: √35 – ∛115 Step 1. Simplify Expression 1. Notice that √9 = 3 and 9 – 7 = 2, so   √7 + 9 – 7 + √9 = √7 + 2 + 3 = √7 + 5. Step 2. Estimate Expression 1. The approximate value of √7 is about 2.6458. Therefore,   √7 + 5 ≈ 2.6458 + 5 = 7.6458. Step 3. Estimate Expression 2. First, √35 is roughly √35 ≈ 5.916. Next, estimate ∛115. Since ∛125 = 5 and 115 is a bit less, a reasonable approximation is ∛115 ≈ 4.86. Thus, Expression 2 ≈ 5.916 – 4.86 = 1.056. Step 4. Compare the two. We found Expression 1 ≈ 7.65 and Expression 2 ≈ 1.06. Therefore,   √7 + 9 – 7 + √9 > √35 – ∛115. Final Answer: √7 + 9 – 7 + √9 > √35 – ∛115.

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Bonus Knowledge

To solve the comparison, let's evaluate both expressions. For the first expression, \( \sqrt{7}+9-7+\sqrt{9} \): - \( \sqrt{7} \) is approximately \( 2.645751311 \), and \( \sqrt{9} = 3 \). - So, it becomes: \[ \sqrt{7} + 9 - 7 + 3 \approx 2.645751311 + 9 - 7 + 3 = 2.645751311 + 5 \approx 7.645751311. \] For the second expression, \( \sqrt{35}-\sqrt[3]{115} \): - \( \sqrt{35} \) is approximately \( 5.916079783 \), and \( \sqrt[3]{115} \) is approximately \( 4.820 \). - So, it becomes: \[ \sqrt{35} - \sqrt[3]{115} \approx 5.916079783 - 4.820 \approx 1.096079783. \] Now we can compare: - The value of the first expression is approximately \( 7.645751311 \), and the value of the second expression is approximately \( 1.096079783 \). Thus, we can conclude that: \[ \sqrt{7}+9-7+\sqrt{9} > \sqrt{35}-\sqrt[3]{115} \] So, the correct inequality is: \( \sqrt{7}+9-7+\sqrt{9} > \sqrt{35}-\sqrt[3]{115} \) or \( 7.645751311 > 1.096079783 \). Thus, the fill would be: \( < \)

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