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find the quotient and remainder using long division. \[ \frac{0 x^{2}-x+5}{3 x^{2}-9 x} \] quotient \( \square \) remainder \( \square \)

Ask by Harris Gibbs. in the United States
Feb 27,2025

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Answer

Quotient: 0 Remainder: –x + 5

Solution

To perform the polynomial long division, we are dividing   Dividend: 0·x² – x + 5   (which is equivalent to –x + 5)   Divisor: 3x² – 9x Step 1. Compare the degrees:   The dividend has degree 1 (since the highest power of x is 1) and the divisor has degree 2.   Since the degree of the dividend is lower than the degree of the divisor, no term in the quotient will allow the leading term of the dividend (0·x²) to match that in the divisor. Step 2. Conclusion from degree comparison:   The quotient is 0, and what remains is the original dividend (–x + 5). Thus, using long division:   Quotient = 0   Remainder = –x + 5 This satisfies the division algorithm:   Dividend = (Divisor × Quotient) + Remainder So, the final answer is:   Quotient: 0   Remainder: –x + 5

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To divide \( 0x^{2} - x + 5 \) by \( 3x^{2} - 9x \) using long division, we first note that the leading term \( 0x^{2} \) in the dividend indicates that we expect the quotient to be a polynomial of lower degree. This means that the degree of the dividend is less than the divisor. Consequently, the entire \( 0x^{2} - x + 5 \) becomes the remainder. Since \( 3x^{2} - 9x \) has a degree of 2 and \( 0x^{2} - x + 5 \) has a degree of 1, we can conclude: Quotient: \( 0 \) Remainder: \( -x + 5 \)

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